SOLUTION: 4. M is between L and N. ML = 4x – 12. MN = x + 2. LN = 40. Find LM. A. 10 B. 12 C. 28 D. 32

Algebra ->  Points-lines-and-rays -> SOLUTION: 4. M is between L and N. ML = 4x – 12. MN = x + 2. LN = 40. Find LM. A. 10 B. 12 C. 28 D. 32       Log On


   



Question 676198: 4. M is between L and N. ML = 4x – 12. MN = x + 2. LN = 40. Find LM.

A. 10
B. 12
C. 28
D. 32

Answer by jpvn2015(54) About Me  (Show Source):
You can put this solution on YOUR website!
The answer is C, 28. Here is how I got it:
If LN = 40, then 40 must equal LM+ MN or 4x-12+x+2.
In other words, 40 = 4x-12+x+2
Combine and add like terms: 40=5x-10
Add ten to both sides: 50 = 5x
Dividing both sides by 5 yields: x=10
So, once we find x (10), we can substitute it in for LM (or ML).
4x - 12
4(10) - 12
40-12
28.
Thus, C is the correct answer.