SOLUTION: find the area of the circle whose equation is x^2+11x+y^2-5y=1 so far i have completed the square and gotten (x^2+11x+121/4)+(y^2-5y+25/4)= 75/2

Algebra ->  Circles -> SOLUTION: find the area of the circle whose equation is x^2+11x+y^2-5y=1 so far i have completed the square and gotten (x^2+11x+121/4)+(y^2-5y+25/4)= 75/2      Log On


   

Question 667686: find the area of the circle whose equation is
x^2+11x+y^2-5y=1
so far i have completed the square and gotten
(x^2+11x+121/4)+(y^2-5y+25/4)= 75/2
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+11x+y^2-5y=1
%28x%5E2%2B11x%2B121%2F4%29%2B%28y%5E2-5y%2B25%2F4%29=+73%2F2%2B1
%28x%5E2%2B11x%2B121%2F4%29%2B%28y%5E2-5y%2B25%2F4%29=+75%2F2

%28x%2B%2811%2F2%29%29%5E2%2B%28y-%285%2F2%29%29%5E2=75%2F2
Radius^2 = 75/2
Area = pi*r^2
=22/7 * 75/2
= 117.86 sq.units

Area = 117.9 sq. units