Question 661569: Find an equation of the circle with center at the origin and passing through (−2−2) in the form of
(x−h)^2+(y−k)^2=r^2 where hkr are constants.
I found radius of 8^(1/2).
h & k are not (2, 2) or (-2, -2). I'm thinking h & k are (4, 4), because it equals to the radius. Please find h & k, thank you!
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find an equation of the circle with center at the origin and passing through (−2−2) in the form of (x−h)^2+(y−k)^2=r^2 where hkr are constants.
I found radius of 8^(1/2).
**
(h,k)=given (x,y) coordinates of center=(0,0)
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