SOLUTION: find the equation of the diameter of the circle x^2+y^2+6x-2y=6 which when produced passes through the point (1,-2). thank you

Algebra ->  Circles -> SOLUTION: find the equation of the diameter of the circle x^2+y^2+6x-2y=6 which when produced passes through the point (1,-2). thank you      Log On


   

Question 636292: find the equation of the diameter of the circle x^2+y^2+6x-2y=6 which when produced passes through the point (1,-2).

thank you
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
The equation of the circle can be expressed as %28x+%2B+3%29%5E2+%2B+%28y+-+1%29%5E2+=+16.
The center of the circle %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 is (h,k) and the radius is r. Therefore, the center of the circle %28x+%2B+3%29%5E2+%2B+%28y+-+1%29%5E2+=+16 is (-3,1).
The slope of line joining (1,-2) and (-3,1) is
m+=+%281-%28-2%29%29%2F%28-3-1%29+=+-3%2F4
The equation of the diameter is
+y+-+%28-2%29+=+%28-3%2F4%29%28x+-+1%29
Answer: highlight%28y+=+%28-3%2F4%29x+-+5%2F4%29