SOLUTION: find the coordinates of the center and radius of the circle by the equation x^2+y^2+½x-3y=27/16=0

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Question 630530: find the coordinates of the center and radius of the circle by the equation x^2+y^2+½x-3y=27/16=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Assuming You meant:

x^2+y^2+ 1/2x-3y+27/16=0  completing the Square

%28x%2B1%2F4%29%5E2+%2B+%28y-3%2F2%29%5E2+-1%2F16+-+9%2F4+%2B+27%2F16+=+10%2F16

 %28x%2B1%2F4%29%5E2+%2B+%28y+-+3%2F2%29%5E2+=+10%2F16   C(-.25, 1.5) and r = sqrt%2810%29/4