Question 621381: Which of the following lines is equidistant fro the points (3,8) and (9,6)?
A)x=1/3
B)y=3
C)y=x/3
D)y=-x/3
E)y=3x+8
Found 2 solutions by ewatrrr, Alan3354:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
Which of the following lines is equidistant fro the points
(3,8) and
(9,6) m = 2/-6 = -1/3 and y = (-1/3)x + 9
any line parallel to above line would be equidistant from these points.
D. y = (-1/3)x would be, same slopes m = (-1/3)
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! Which of the following lines is equidistant fro the points (3,8) and (9,6)?
A)x=1/3
B)y=3
C)y=x/3
D)y=-x/3
E)y=3x+8
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The line equidistant is the perpendicular bisector.
The slope of the line thru the 2 points is -1/3, perpendicular lines have a slope of +3
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Only E has a slope of 3
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The point midway between the 2 points is (6,7)
The line has a slope of 3 and passes thru (6,7)
7 = 3*6 + b
b = -11
y = 3x - 11 is the equation of the line that is the locus of points equidistant from the 2 points.
--> None of the choices
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This is poorly worded and subject to interpretation. Math problems should be explicit.
The other tutor solved for a different meaning.
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