SOLUTION: write the equation of a circle ,in standard form, whose endpoints of its diameter (-3,2) and (3,-6)

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Question 614586: write the equation of a circle ,in standard form, whose endpoints of its diameter (-3,2) and (3,-6)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

write the equation of a circle ,in standard form, whose endpoints of its diameter:

 (-3,2) and 

 (3,-6)   Midpoint = (0,-2) and radius = %281%2F2%29sqrt%28+%28-6%29%5E2+%2B+8%5E2%29%29 = 5

 equation of a circle:  +x%5E2+%2B+%28y%2B2%29%5E2+=+5%5E2

Note:

D = sqrt+%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29%29

Midpoint Pt(x,y):  ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29)