Question 604360: Write an equation of a circle tangent to the lines x=2 and x=12 and passes through the point (4,0)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write an equation of a circle tangent to the lines x=2 and x=12 and passes through the point (4,0)
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Draw the 2 vertical lines: x = 2 and x = 12
Plot the point (4,0)
The lines implie the diameter is 10 (radius = 5).
The center is at (7,k)
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Equation:
(x-7)^2 + (y-k)^2 = 5^2
Solve for "k" using (4,0) as a point on the circle:
(4-7)^2 + (0-k)^2 = 25
9 + k^2 = 25
k^2 = 16
k = 4
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Equation:
(x-7)^2 + (y-4)^2 = 25
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Cheers,
Stan H.
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