Question 602331: What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36 Found 2 solutions by nerdybill, Alan3354:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36
.
Standard equation of a circle:
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) is the center
r is the radius
.
You were given:
(x+5)^2+(y-1)^2=36
which can be written as:
(x-(-5))^2+(y-1)^2=36
so, from inspection then, the center is at:
(-5, 1)
You can put this solution on YOUR website! What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36
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A circle is
--> (-5,1)
