|
Question 591931: Find an equation of the line that passes through the point (1,-3) and is parallel to the line 8x-4y=-4.
a) 8x-4y=20
b) x-3y=-4
c) 8x-4y=-28
d) 8x+4y=-4
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! We first solve 8x-4y = -4 for y.
-4y = -8x - 4
y = (-8x - 4)/-4
y = 2x + 1
We now use the point-slope formula and the slope just found. The slope is the coefficient of x in the equation y = 2x + 1. The slope is 2.
Let (1,-3) = (a,b)
The point-slope formula is y - b = slope(x - a).
y - (-3) = 2(x - 1)
y + 3 = 2x - 2
y = 2x - 2 - 3
y = 2x - 5
The equation y = 2x - 5 is EXACTLY the same equation given in choice (a).
The answer is choice (a).
If you have a fax number, I can fax my answers to you for other questions that you may have. It is easier to write on paper and then fax my answers to students. If you have a fax number, send it to: nycfunction@yahoo.com
Mr. Feliz
|
|
|
| |
