SOLUTION: This is a 2-part question:
1. The equation of a circle is (x-h)^2+(y-h)^2=r^2 where(h,k) is the center and r is the center of this circle. Find the area and center of this circl
Algebra ->
Circles
-> SOLUTION: This is a 2-part question:
1. The equation of a circle is (x-h)^2+(y-h)^2=r^2 where(h,k) is the center and r is the center of this circle. Find the area and center of this circl
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Question 588139: This is a 2-part question:
1. The equation of a circle is (x-h)^2+(y-h)^2=r^2 where(h,k) is the center and r is the center of this circle. Find the area and center of this circle. x^2+y^2=36
2. Find the area of the square inscribed in the circle in the previous (the question above) problem. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1. The equation of a circle is (x-h)^2+(y-h)^2=r^2 where(h,k) is the center and r is the center of this circle. Find the area and center of this circle. x^2+y^2=36
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Center: (0,0)
radius: sqrt(36) = 6
Area = (pi)r^2 = 36pi sq. units
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2. Find the area of the square inscribed in the circle in the previous (the question above) problem.
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Side of the square = the diameter of the circle = 12
Area of the square = side^2 = 144 sq. units
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Cheers,
Stan H.
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