SOLUTION: Given: Radius OR is perpendicular to chord AB at C AC=2(x-3), BC=x+8 Find: AC, BC, and AB

Algebra ->  Circles -> SOLUTION: Given: Radius OR is perpendicular to chord AB at C AC=2(x-3), BC=x+8 Find: AC, BC, and AB      Log On


   

Question 554037: Given:
Radius OR is perpendicular to chord AB at C
AC=2(x-3), BC=x+8
Find: AC, BC, and AB
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
If the radius, OR, is perpendicular to chord AB, then it bisects AB so that AC = BC.
2(x-3) = x+8 Solve for x.
2x-6 = x+8
x = 14 so...
AC = 2(x-3) = 2(14-3) = 22.
BC = x+8 = 14+8 = 22.
AB = AC + BC = 22+22 = 44.