SOLUTION: if ABCD is a square of area of 4 sq cm, find the radius of the circle that passes through all the vertices of the square.
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-> SOLUTION: if ABCD is a square of area of 4 sq cm, find the radius of the circle that passes through all the vertices of the square.
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Area = 4cm^2
side = 2
Use Pythagoras theorem
diagonal = hypotenuse
diagonal ^2= side1^2+side2^2
diagonal^2=2^2+2^2
diagonal^2=8
diagonal = sqrt(8)
the radius of the sircle will be 1/2 the diagonal
sqrt(8)/2
=2sqrt(2)/2
=sqrt(2)
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