Question 536317: Find the equation of the circle of radius 5 whose centre lies on x-axis and passes through the point (2,3). Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The distance from the x-axis to (2,3) is the radius, r = 5.
There are 2 points in the x-axis that are 5 units from the point (2,3).
The points are (x,0).
(x - 6)*(x + 2) = 0
x = -2, x = 6
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Circle 1 Circle 2
