SOLUTION: find the center and radius of the circle with equation x2-4x+y2-6y+9=0.

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Question 534146: find the center and radius of the circle with equation x2-4x+y2-6y+9=0.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Find the center and radius:
x%5E2-4x%2By%5E2-6y%2B9+=+0 Complete the square in x by adding the square of half the x-coefficient %28-4%2F2%29%5E2+=+4 to both sides.
%28x%5E2-4x%2B4%29%2B%28y%5E2-6y%2B9%29+=+4 Now factor the x-terms and the y-terms.
%28x-2%29%5E2%2B%28y-3%29%5E2+=+4 Compare with the standard form for a circle with center at (h,k) and radius r:
%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2
You can see that the center is at (2,3) and the radius is 2.