SOLUTION: A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of the circle. What is the ratio of the area of the sq

Algebra ->  Circles -> SOLUTION: A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of the circle. What is the ratio of the area of the sq      Log On


   



Question 521597: A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of the circle. What is the ratio of the area of the square to the area of the circle? Express your answer as a common fractin in terms of Pie.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of the circle.
What is the ratio of the area of the square to the area of the circle? Express your answer as a common fraction in terms of Pie.
:
Let r = the side of the square and the radius of the circle
:
Square area: circle area: r%5E2%2F%28pi%2Ar%5E2%29, r^2 cancel leaving 1%2Fpi