SOLUTION: I am trying to determine if this equation is a circle and give center and radius. I know it is a circle because x and y have equal coefficients and I know the formula but I can't f
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-> SOLUTION: I am trying to determine if this equation is a circle and give center and radius. I know it is a circle because x and y have equal coefficients and I know the formula but I can't f
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Question 505281: I am trying to determine if this equation is a circle and give center and radius. I know it is a circle because x and y have equal coefficients and I know the formula but I can't figure how to set it up. Equation is: x^2+y^2-12x+10y = -25. Thank you Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
.
For your problem:
x^2+y^2-12x+10y = -25
group x's and y's:
(x^2-12x)+(y^2+10y) = -25
complete the squares:
(x^2-12x+36)+(y^2+10y+25) = -25+36+25
(x-6)^2+(y+5)^2 = 36
(x-6)^2+(y+5)^2 = 6^2
.
Center: (6,5)
Radius: 6
