Question 503593: find the standard form of the circle with a center of (-4,10) and passes through (-2,-4)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the standard form of the circle with a center of (-4,10) and passes through (-2,-4)
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Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates of the center, r=radius.
For given equation:
(x+4)^2+(y-10)^2=r^2
solving for r using (x,y) coordinates of given point (-2,-4)
(-2+4)^2+(-4-10)^2=r^2
(2)^2+(-14)^2=r^2
4+196=r^2
r^2=200
Equation:
(x+4)^2+(y-10)^2=200
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