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Question 483256: write the equation in point slope form for a line that passes through(-4,6) and is perpendicular to the line 2x+3y=12
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! 2 x + 3 y = 12
Find the slope of this line
3 y = -2 x + 12
Divide by 3
y = - 2/3 x + 4
Compare this equation with y=mx+b
slope m = -2/3
The slope of a line perpendicular to the above line will be the negative reciprocal 3/2
m1*m2=-1
The slope of the required line will be 3/2
m= 3/2 ,point ( -4 , 6 )
Find b by plugging the values of m & the point in
y=mx+b
6 = -6.00 + b
b= 12
m= 1 1/2
The required equation is y =3/ 2x+12
m.ananth@hotmail.ca
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