SOLUTION: My question is: Find the standard form of the equation for a circle with center (3, − 1) and solution point (−5, 1) . Can you please explain how to solve it for futu

Algebra ->  Circles -> SOLUTION: My question is: Find the standard form of the equation for a circle with center (3, − 1) and solution point (−5, 1) . Can you please explain how to solve it for futu      Log On


   



Question 478813: My question is: Find the standard form of the equation for a circle with center (3, − 1) and solution point (−5, 1) .
Can you please explain how to solve it for future reference :). Thank You

Found 2 solutions by mananth, ewatrrr:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Distance between two points Center ( 3,-1) and a solution point (-5,1) will give us the radius
x1 y1 x2 y2
3 -1 -5 1
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
d= sqrt%28%281-%28-1%29%29%5E2%2B%28-5-%093%29%5E2%29
d= sqrt%28%282%29%5E2%2B%28-8%29%5E2%29
d= sqrt%28%2868%29%29
d= 8.25 = radius
%28x-3%29%5E2%2B%28y%2B1%29%5E2=+%288.25%29%5E2
m.ananth@hotmail.ca

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
circle with center (3,-1)and solution point (-5,1)
%28x-3%29%5E2+%2B+%28y%2B1%29%5E2+=+r%5E2
r is the distance from the Center(3,-1) to the point on the circle (-5,1)
D = sqrt+%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29= sqrt%288%5E2+%2B+%28-2%29%5E2%29+=+sqrt%2868%29=+r
%28x-3%29%5E2+%2B+%28y%2B1%29%5E2+=+68
Conics in general:
Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola opening right and left is:
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 where Pt(h,k) is a center with vertices 'b' units up and down from center.
the vertex form of a parabola opening up or down, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex.
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)
the vertex form of a parabola opening right or left, x=a%28y-k%29%5E2+%2Bh where(h,k) is the vertex.
The standard form is %28y+-k%29%5E2+=+4p%28x+-h%29, where the focus is (h +p,k )