SOLUTION: need help,word problem..a sign must be 110 inches, the length is 15 inches longer than it's width. w= length= find the dimentions thanks so much

Algebra ->  Points-lines-and-rays -> SOLUTION: need help,word problem..a sign must be 110 inches, the length is 15 inches longer than it's width. w= length= find the dimentions thanks so much      Log On


   

Question 471114: need help,word problem..a sign must be 110 inches, the length is 15 inches longer than it's width. w= length= find the dimentions thanks so much
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
The equation for the perimeter of the sign would be:
P = 2L + 2W
since L = W + 15, you can substitute in that equation to get:
P = 2(W+15) + 2W to get:
P = 2W + 30 + 2W = 110
This becomes:
4W + 30 = 110
subtract 30 from both sides to get:
4W = 80
divide both sides by 4 to get:
W = 20
Your perimeter equation becomes:
2L + 40 = 110
subtract 40 from both sides to get:
2L = 70
divide both sides by 2 to get:
L = 35
you have:
L = 35
W = 20
L is 15 more than W
2L + 2W = 110
that should be your answer.