SOLUTION: the circle centered at B is internally tangent to the circle centered at A. The smaller circle passes through the center of the larger circle and the length of AB
is 5units. If th
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-> SOLUTION: the circle centered at B is internally tangent to the circle centered at A. The smaller circle passes through the center of the larger circle and the length of AB
is 5units. If th
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Question 466105: the circle centered at B is internally tangent to the circle centered at A. The smaller circle passes through the center of the larger circle and the length of AB
is 5units. If the smaller circle IS REMOVED FROM THE LARGER CIRCLE, how much of the area,in square units, of the larger circle will remain? Answer by Edwin McCravy(20064) (Show Source):
The area of the larger circle is found with formula:
A = pr²
The radius of the larger circle is 10 units,
so its area is
A = p(10)² = p*100 = 100p square units.
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The area of the smaller circle is also found with formula
A = pr²
The radius of the smaller circle is 5 units.
so its area is
A = p(5)² = p*15 = 25p square units.
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Therefore when we remove the small circle, the area that's left is
100p - 25p square units, or
(100-25)p square units or
75p square units or approximately 235.6 square units.
Edwin
