SOLUTION: How do you find the standard form of the equation of a circle, with a center (-1,5) through the point (23,-2)?

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Question 451739: How do you find the standard form of the equation of a circle, with a center (-1,5) through the point (23,-2)?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

where Pt(h,k) is the center and r is the radius

center (-1,5)

%28x%2B1%29%5E2+%2B+%28y-5%29%5E2+=+r%5E2



(-1,5)

(23,-2) D = sqrt+%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29%29 = 

        D = sqrt%28+%28-24%29%5E2%2B%287%29%5E2%29 = sqrt+%28625%29 = 25

%28x%2B1%29%5E2+%2B+%28y-5%29%5E2+=+625