SOLUTION: Find the center of the circle with equation x^2+2x+y^2-10y+22=0. I plotted it to be (-2.4) but not sure if it is right. Thanks for checking it.

Algebra ->  Points-lines-and-rays -> SOLUTION: Find the center of the circle with equation x^2+2x+y^2-10y+22=0. I plotted it to be (-2.4) but not sure if it is right. Thanks for checking it.      Log On


   

Question 43368This question is from textbook algebra and trigonometry with analytic geometry
: Find the center of the circle with equation x^2+2x+y^2-10y+22=0. I plotted it to be (-2.4) but not sure if it is right. Thanks for checking it. This question is from textbook algebra and trigonometry with analytic geometry

Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
You are wrong!

x%5E2+%2B+2x+%2B+y%5E2+-+10y+%2B+22+=+0
or
or %28x%2B1%29%5E2+%2B+%28y-5%29%5E2+%2B+22+-+1+-+25+=+0
or %28x%2B1%29%5E2+%2B+%28y-5%29%5E2+-+4+=+0
or %28x%2B1%29%5E2+%2B+%28y-5%29%5E2+=+4
or %28x%2B1%29%5E2+%2B+%28y-5%29%5E2+=+2%5E2

So the given equation represents a circle with centre at (-1,5) and radius 2 units.