Hi
circle whose diameter has endpoints of (3, 0) and (7, 10)
(3, 0) and
(7, 10) Midpoint is (5,5) | (
,
)
(3, 0) and
(7, 10 D = sqrt( (-4)^2 + (-10)^2)) | D =
D = sqrt(116) = 2sqrt(29) and r = sqrt(29)
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius
(x-5)^2 + (y-5)^2 = 29