SOLUTION: What is the equation of the line that passes through the point (6, -5) and is parallel to the line whose equation is 2x - 3y = 11?
1. y + 5 = 3/2 (x-6)
2. y = 2/3x + 1
3. y
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-> SOLUTION: What is the equation of the line that passes through the point (6, -5) and is parallel to the line whose equation is 2x - 3y = 11?
1. y + 5 = 3/2 (x-6)
2. y = 2/3x + 1
3. y
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Question 408018: What is the equation of the line that passes through the point (6, -5) and is parallel to the line whose equation is 2x - 3y = 11?
1. y + 5 = 3/2 (x-6)
2. y = 2/3x + 1
3. y = -3/2x + 4
4. y + 5 - 2/3(x-6) Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! I will walk you through with one.
(6, -5) and is parallel to the line whose equation is 2x - 3y = 11?
2x - 3y = 11
add 3y to both sides
2x=11+3y
-11
2x-11=3y
3y=2x-11
/3
y= (2/3)*x-11/3
slope m = 2/3
The parallel line will have the same slope as that of the given line.
so slope of the required line will be 2/3
..
line passes through (6,-5)
plug the value of slope , and the point (6,-5) to find b the y intercept
of the required line
y=mx+b
-5=2/3 *6+b
-5=4+b
b=-9
...
so the equation has slope 2/3 and y intercept -9
y=(2/3)x-9
...
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