SOLUTION: May you please help me with this problem. One thing i know is the center of a circle is (h,k) Find the center of the circle given by x^2 + 10x + 41 +y^2 -8y = 36. May yo

Algebra ->  Circles -> SOLUTION: May you please help me with this problem. One thing i know is the center of a circle is (h,k) Find the center of the circle given by x^2 + 10x + 41 +y^2 -8y = 36. May yo      Log On


   

Question 402398: May you please help me with this problem.
One thing i know is the center of a circle is (h,k)

Find the center of the circle given by x^2 + 10x + 41 +y^2 -8y = 36.
May you explain in dtail in how you solved the problem please
Thank you,
jgomez123

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
a general equation for a circle is ___ (x - h)^2 + (y - k)^2 = r^2
___ where (h,k) is the center and r is the radius

so you need to complete the squares for x and y to get the equation into the general form

(x^2 + 10x) + (y^2 - 8y) = 36 - 41

(x^2 + 10x + 25) + (y^2 - 8y + 16) = -5 + 25 + 16

(x + 5)^2 + (y - 4)^2 = 36