SOLUTION: I can't figure this question out! Please help me! :) " For what values of k is y=k a tangent to the circle (x+3)^2+(y+3)^2=25 "

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Question 396992: I can't figure this question out! Please help me! :)
" For what values of k is y=k a tangent to the circle (x+3)^2+(y+3)^2=25 "
Found 2 solutions by scott8148, Alan3354:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
y=k is a horizontal line, so the tangents would be at the top and bottom of the circle

the circle is centered at (-3,-3) with a radius of 5

the top of the circle is at y=2 , and the bottom is at y=-8

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
" For what values of k is y=k a tangent to the circle (x+3)^2+(y+3)^2=25 "
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The center is at (-3,-3) and the radius = 5
The "top" and "bottom" are at y = -3 + 5 and -3 -5.
The lines y = 2 and y = -8 are tangent.
k = 2, -8