SOLUTION: A line passing through (6,10) and (-1,y) is perpendicular to a line with slope 7/2. Find the value of y. Any help would be helpful tryign to figure out points and slop and like t

Algebra ->  Points-lines-and-rays -> SOLUTION: A line passing through (6,10) and (-1,y) is perpendicular to a line with slope 7/2. Find the value of y. Any help would be helpful tryign to figure out points and slop and like t      Log On


   

Question 383114: A line passing through (6,10) and (-1,y) is perpendicular to a line with slope 7/2. Find the value of y.
Any help would be helpful tryign to figure out points and slop
and like to see how it is done . i am a viuable person
Thank you
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A line passing through (6,10) and (-1,y) is
perpendicular to a line with slope 7/2.
Find the value of y.
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The slope determined by the 2 points: m = (y-10)/(-1-6) = (y-10)/-7
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To be perpendicular to a line with slope = 7/2
our line must have a slope of -2/7.
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Solve:
(y-10)/-7 = -2/7
(y-10)/-7 = 2/-7
y-10 = 2
y = 12
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Cheers,
Stan H.