SOLUTION: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0.

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Question 383021: find the radius of the circle defined by the equation: 3x^2+3y^2+12x-12x-48=0.
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2+3y^2+12x-12x-48=0=>x^2+y^2=16 => radius is 4.