SOLUTION: Need a little help please. Question: A simple dartboard has three areas� the main board has a radius of 10 inches, there is a circle with a radius of 7 inches, and the bullseye

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Question 381347: Need a little help please.
Question: A simple dartboard has three areas� the main board has a radius of 10 inches, there is a circle with a radius of 7 inches, and the bullseye has a radius of 3 inches. What is the probability of a random dart landing inside the bullseye?

Found 2 solutions by stanbon, richard1234:
Answer by stanbon(75887) (Show Source):
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A simple dartboard has three areas� the main board has a radius of 10 inches, there is a circle with a radius of 7 inches, and the bullseye has a radius of 3 inches. What is the probability of a random dart landing inside the bullseye?
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Prob(bullseye) = (area of bullseye)/(area of board)
= (pi*7^2)/(pi*10^2) = 49/100
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Cheers,
Stan H.

Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website!
The area of the bullseye is pi*(3^2) = 9pi, and the area of the whole board is pi*(10^2) = 100pi. Therefore the probability is 9/100.