SOLUTION: I need help to find the x and y intercepts of these circles. Circle 1 (x+2)^2+(y+3)^2=4 and Circle 2 x^2+y^2-18x-2y+66=0. Thanks in advance!!!!

Algebra ->  Circles -> SOLUTION: I need help to find the x and y intercepts of these circles. Circle 1 (x+2)^2+(y+3)^2=4 and Circle 2 x^2+y^2-18x-2y+66=0. Thanks in advance!!!!       Log On


   

Question 380874: I need help to find the x and y intercepts of these circles. Circle 1 (x+2)^2+(y+3)^2=4 and Circle 2 x^2+y^2-18x-2y+66=0.
Thanks in advance!!!!
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Circle 1: Letting y = 0 to solve for the x-int, we get +%28x%2B2%29%5E2+%2B+9=4. This equation has no solution, hence there are no x-intercepts.
Letting x = 0 to find the y-int, we get4%2B%28y%2B3%29%5E2=4. The only solution is y =-3.Thus the y-intercept is (0,-3).
Circle 2: Let y = 0 to find the x-int. Then x%5E2-18x%2B66=0. The solutions to this are x+=+%2818+%2B-+sqrt%2860+%29%29%2F2+=+9+%2B-+sqrt%2815+%29. These are also the x-intercepts.
Let x = 0 to find the y-int. Then y%5E2-2y%2B66=0. This equation has no real roots. Therefore there are no y-intercepts.