SOLUTION: Find the radius of the circle defined by the equation: 5x^2+5y^3+60x+40y+215=0.
It tells me that the standard form of the equation of a circle is (x-h)^2+(y-k)^2=r^2 , but how do
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-> SOLUTION: Find the radius of the circle defined by the equation: 5x^2+5y^3+60x+40y+215=0.
It tells me that the standard form of the equation of a circle is (x-h)^2+(y-k)^2=r^2 , but how do
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Question 376188: Find the radius of the circle defined by the equation: 5x^2+5y^3+60x+40y+215=0.
It tells me that the standard form of the equation of a circle is (x-h)^2+(y-k)^2=r^2 , but how do I go about putting this equation into standard form? I'm a bit confused please help. Answer by Fombitz(32388) (Show Source):
