SOLUTION: Find the center of the circle defined by the equation 4x^2+ 4y^2+24x-56y +168=0

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Question 375826: Find the center of the circle defined by the equation 4x^2+ 4y^2+24x-56y
+168=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B+4y%5E2%2B24x-56y%2B168=0
x%5E2%2B+y%5E2%2B6x-14y%2B42=0
%28x%5E2%2B6x%29%2B+%28y%5E2-14y%29%2B42=0
%28x%5E2%2B6x%2B9%29%2B+%28y%5E2-14y%2B49%29%2B42=9%2B49
%28x%2B3%29%5E2%2B+%28y-7%29%5E2=16
Compare to the equation of a circle centered at (h,k) with radius R,
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
h=-3
k=7