SOLUTION: nothing like the examples . . .y^2-12y+6x+30=0 . . find vertex, focus and directrix of the parabola . . y^2-12y+30=-6x . .now I can not figure out how to factor it and solve theres

Algebra ->  Circles -> SOLUTION: nothing like the examples . . .y^2-12y+6x+30=0 . . find vertex, focus and directrix of the parabola . . y^2-12y+30=-6x . .now I can not figure out how to factor it and solve theres      Log On


   



Question 375717: nothing like the examples . . .y^2-12y+6x+30=0 . . find vertex, focus and directrix of the parabola . . y^2-12y+30=-6x . .now I can not figure out how to factor it and solve therest.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E2-12y%2B6x%2B30=0,
y%5E2-12y+=+-6x+-+30,
y%5E2-12y+%2B36=-6x-30+%2B+36,
%28y-6%29%5E2+=+-6%28x+-+1%29. The vertex is (h,k) = (1,6). (The parabola has axis parallel to the x-axis, and opens to the left.)
The focus: -4c = -6, or c = 3/2. Point-wise, the focus is (-1/2, 6).
The directrix is the the vertical line x = 1 + 3/2, or x = 5/2.
(The coordinates of the latus recta are (-1/2, 9) and (-1/2, 3).)