SOLUTION: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.

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Question 372724: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
x%5E2%2By%5E2%2B12x%2B8y%2B16=0
%28x%5E2%2B12x%2B36%29%2B%28y%5E2%2B8y%2B16%29%2B16=36%2B16
%28x%2B6%29%5E2%2B%28y%2B4%29%5E2=36
Compare to the general equation for a circle centered at (h,k) with a radius R:
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2