SOLUTION: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.
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Question 372724
:
Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0.
Answer by
Fombitz(32388)
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Complete the square in
and
.
Compare to the general equation for a circle centered at (
,
) with a radius
: