SOLUTION: Find the center of the circle defined by the equation x^2+y^2+16x+10y+53=0 The question want you to put it in this form (x-h)^2+(y-k)^2=r^2

Algebra ->  Circles -> SOLUTION: Find the center of the circle defined by the equation x^2+y^2+16x+10y+53=0 The question want you to put it in this form (x-h)^2+(y-k)^2=r^2       Log On


   

Question 372504: Find the center of the circle defined by the equation x^2+y^2+16x+10y+53=0
The question want you to put it in this form
(x-h)^2+(y-k)^2=r^2

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
x%5E2%2B16x%2By%5E2%2B10y%2B53=0
%28x%5E2%2B16x%2B64%29%2B%28y%5E2%2B10y%2B25%29%2B53=64%2B25
%28x%2B8%29%5E2%2B%28y%2B5%29%5E2%2B53=89
highlight%28%28x%2B8%29%5E2%2B%28y%2B5%29%5E2=36%29