SOLUTION: I have a problem with simplifying this ratio: 2a+2b+2c/2(pi)a+2(pi)b+2(pi)c Pi being the number pi

Algebra ->  Circles -> SOLUTION: I have a problem with simplifying this ratio: 2a+2b+2c/2(pi)a+2(pi)b+2(pi)c Pi being the number pi      Log On


   

Question 36507This question is from textbook Geometry: Seeing, Doing, Understanding
: I have a problem with simplifying this ratio:
2a+2b+2c/2(pi)a+2(pi)b+2(pi)c


Pi being the number pi This question is from textbook Geometry: Seeing, Doing, Understanding

Answer by astromathman(21) About Me  (Show Source):
You can put this solution on YOUR website!
I am going to assume you mean (2a+2b+2c)/(2(pi)a+2(pi)b+2(pi)c), or in other words, %282a%2B2b%2B2c%29%2F%282%2Api%2Aa%2B2%2Api%2Ab%2B2%2Api%2Ac%29
If that is what you meant, first factor 2 from the three terms of the numerator and 2%2Api from the three terms of the denominator: 2%2A%28a%2Bb%2Bc%29%2F%282%2Api%28a%2Bb%2Bc%29%29. Now cancel 2 and (a+b+c) to get the result: 1%2Fpi