SOLUTION: I don't know anything about geometry and I need to help my 4th grade son. Please help on the following using a graph: 1. Draw four points on the graph of the equation y =3x +

Algebra ->  Points-lines-and-rays -> SOLUTION: I don't know anything about geometry and I need to help my 4th grade son. Please help on the following using a graph: 1. Draw four points on the graph of the equation y =3x +      Log On


   

Question 35338: I don't know anything about geometry and I need to help my 4th grade son.
Please help on the following using a graph:
1. Draw four points on the graph of the equation y =3x + 1. Connect using a straight line.
2. Draw four points on the graph of the equation y =2x - 1. Connect using a straight line.
3. Draw four points on the graph of the equation y = x + 1. Connect using a straight line.
Draw four points on the graph of the equation y = 2x Connect using a straight line.

Thank you.
Maritza
Answer by lyra(94) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 3+x+%2B+-1+y+=+-1 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-3%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -1/3 = -0.333333333333333.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -1/-1 = 1.
  • Slope is -3/-1 = 3.
  • Equation in slope-intercept form: y=3*x+1.

You can find points by plugging numbers into the equation.
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 2+x+%2B+-1+y+=+1 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-2%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 1/2 = 0.5.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 1/-1 = -1.
  • Slope is -2/-1 = 2.
  • Equation in slope-intercept form: y=2*x+-1.
graph%28+500%2C+500%2C+0.5-8%2C+0.5%2B8%2C+-1-8%2C+-1%2B8%2C+2%2Ax%2B-1+%29+

You can find points by plugging numbers into the equation.
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 1+x+%2B+-1+y+=+-1 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-1%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -1/1 = -1.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -1/-1 = 1.
  • Slope is -1/-1 = 1.
  • Equation in slope-intercept form: y=1*x+1.
graph%28+500%2C+500%2C+-1-8%2C+-1%2B8%2C+1-8%2C+1%2B8%2C+1%2Ax%2B1+%29+

You can find points by plugging numbers into the equation.
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 2+x+%2B+-1+y+=+0 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-2%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/2 = 0.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/-1 = 0.
  • Slope is -2/-1 = 2.
  • Equation in slope-intercept form: y=2*x+0.
graph%28+500%2C+500%2C+0-8%2C+0%2B8%2C+0-8%2C+0%2B8%2C+2%2Ax%2B0+%29+

You can find points by plugging numbers into the equation.
Hope this helps and feel free to contact me for further help,
lyra