SOLUTION: Write the equation of a line that is perpendicular to y=-5x-4 and passes through (-35, 10) Please help! :)

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Question 351467: Write the equation of a line that is perpendicular to y=-5x-4 and passes through (-35, 10) Please help! :)
Found 2 solutions by stanbon, jojo14344:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation of a line that is perpendicular to y=-5x-4 and passes through (-35, 10)
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The given line has slope = -5
----
Any line perpendicular to the given line
must have a slope of 1/5.
------------------------------
Form: y = mx+b
10 = (1/5)(-35) = b
b = 10+7
b = 17
----
Equation:
y = (1/5)x+17
================
Cheers,
Stan H.
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Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


A line equation follows---> y=mx%2Bb, where m=slope

If given line y=-5x-4 has a slope=m%5B1%5D=-5, then we know that line perpendicular to it has a slope value m%5B2%5D that is "negative reciprocal" of m%5B1%5D ----> m%5B2%5D=-1%2Fm%5B1%5D=-1%2F-5=red%281%2F5%29.

Knowing m%5B2%5D=1%2F5, a line through (-35,10) via Slope intercept form y=mx%2Bb:
10=%281%2F5%29%28-35%29%2Bb ---> 10=%281%2Fcross%285%291%29%28cross%28-35%297%29%2Bb
10=-7%2Bb
b=10%2B7=17, Y-inetercept

Therefore, it follows highlight%28y=%281%2F5%29x%2B17%29 (Answer) ----> that is perpendicular to line y=-5x-4:


Thank you,
Jojo