SOLUTION: Im not to sure if you can help as this is a Pre Calc/Trig question but my father highly recommended this site and this is the first time I've not been able to understand something
Algebra ->
Circles
-> SOLUTION: Im not to sure if you can help as this is a Pre Calc/Trig question but my father highly recommended this site and this is the first time I've not been able to understand something
Log On
Question 338589: Im not to sure if you can help as this is a Pre Calc/Trig question but my father highly recommended this site and this is the first time I've not been able to understand something in my class.
We are currently studying unit circles, and trigonometry of real numbers. The one thing I seem to be having a problem with is understanding how they figure out which quadrant a terminal angle lands in. For instance...
Angle Theta = 5(pie)/6
The reference of Angle Theta is (pie/6)
I understand that the associated point of this Angle is (square root of three/2, 1/2) but this is a generic point and has no reference to where the terminal angle lands...
so how is it known that the Angle Terminates in Quadrant II?
Thank you for your time!
Aaron Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
.
.
.
Angles are measured counterclockwise starting at the positive x-axis.
The point associated with is (,)
.
.
.
The quadrants are divided by the and axes.
The positive x-axis is , radians (, degrees).
The positive y-axis is radians ( degrees).
The negative x-axis is radians ( degrees).
The negative x-axis is radians ( degrees).
.
.
.
So then the quadrant contain the angles in between those values,
Quadrant I : radians, degrees
Quadrant II : radians, degrees
Quadrant III : radians, degrees
Quadrant IV : radians, degrees
.
.
.
Since is between and , it lands in the second quadrant.