SOLUTION: Show that the equation represents a circle, and find the center and radius of the circle. 2X^2 + 2Y^2 - 3X = 0

Algebra ->  Circles -> SOLUTION: Show that the equation represents a circle, and find the center and radius of the circle. 2X^2 + 2Y^2 - 3X = 0      Log On


   

Question 310855: Show that the equation represents a circle, and find the center and radius of the circle.
2X^2 + 2Y^2 - 3X = 0
Answer by solver91311(24713) About Me  (Show Source):
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You know that the equation represents a circle because the coefficients on the squared variables are equal.

To find the center, complete the square. Since there is no first degree y term, the square is already complete on y, hence the y coordinate of the center is zero.

Divide the equation by the coefficient on x.



Divide the coefficient on the first degree x term by 2, then square the result. Add that result to both sides of the equation.



Factor the perfect square trinomial in x:



The center is at and the radius is


John