SOLUTION: 3x^2+3y^2+30x+30y+150=0 a circle is difined by the following equation: what are the coordinates of its center

Algebra ->  Circles -> SOLUTION: 3x^2+3y^2+30x+30y+150=0 a circle is difined by the following equation: what are the coordinates of its center       Log On


   

Question 308325: 3x^2+3y^2+30x+30y+150=0 a circle is difined by the following equation:
what are the coordinates of its center
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
3x^2+3y^2+30x+30y+150=0
%28x%5E2%2B10x%2B25%29%2B%28y%5E2%2B10y%2B25%29%2B50=25%2B25
%28x%2B5%29%5E2%2B%28y%2B5%29%5E2%2B50=50
%28x%2B5%29%5E2%2B%28y%2B5%29%5E2=0
The general equation for a circle of radius R centered at (h,k) is,
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
Comparing, it's a circle centered at (-5,-5) with a radius of 0.