Question 287543: I am having trouble with this problem. I can't figure out how to post a diagram so I will try and describe it. If you can tell me how to post it or give me an email to send it I would be happy to do that.
I have a circle with a diameter drawn in. The radius (indicated on half my diam.) is labeled x. The end of x that is on the circle is also the endpoint of a chord. The other end of the chord connets back to the center of the circle, forming a triangle that looks ALMOST like a rt, triangle, but its not. An arc with a measument of 86 deg. connects the end of the chord that is NOT my radius to the end of the diagonal that is NOT the radius labeled x.
I figured that the angle of my triangle with its vertex as the circle center is 94 degrees since its complimentary angle is 86 degrees. If I draw a radius that is perpendicular to the chord, the angle (by circle center) would be 47 degrees, right? The angle on the circumference where x connects would be 43 degrees, and the leg of my rt. triangle I created w the radius would be 10 in. I just don't get how to solve for x. And I am worried my reasoning is wrong. Please can you walk me through this problem?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! I think you have to have at least 1 dimension here to find x; the length of the
chord or the length of the line from the center that bisects the chord. Also I
think you mean "...since it's supplementary angle is 86 degrees."
:
Your reasoning is correct as far as I understand it
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