SOLUTION: a cake has three circular tires; each is 8 cm high. the tiers have diameters 60 cm, 48 cm, 36 cm. what is the surface area to be covered by frosting? there is no frosting between
Algebra ->
Circles
-> SOLUTION: a cake has three circular tires; each is 8 cm high. the tiers have diameters 60 cm, 48 cm, 36 cm. what is the surface area to be covered by frosting? there is no frosting between
Log On
Question 286572: a cake has three circular tires; each is 8 cm high. the tiers have diameters 60 cm, 48 cm, 36 cm. what is the surface area to be covered by frosting? there is no frosting between layers Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! The surface area of a circle is given by A = 4pi(r^2), where pi = 3.14.
The cake with diameter 60cm has a radius of 30cm.
The cake with diameter 48cm has a radius of 24cm.
The cake with diameter 36cm has a radius of 18cm.
What do you think can be done with this information to find the total surface area?
You need to use the formula above 3 times (one for each cake tire).
Total frosting on cake = 4(3.14)(30cm)^2 + 4(3.14)(24cm)^2 + 4(3.14)(18cm)^2
You can take it from here.
