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Question 285263: Wite the equation of a line through the point (-6,3) parallel and perpendicular to the line 2x+3y=1.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Wite the equation of a line through the point (-6,3) parallel and perpendicular to the line 2x+3y=1.
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Put the given equation in slope-intercept form:
y = (-2/3)x+(1/3)
slope = -2/3
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Any parallel line must have slope = -2/3
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Any perpendicular line must have slope = 3/2
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Equation of the parallel line thru (-6,-3)
-3 = (-2/3)(-6) + b
-3 = 4 + b
b = -7
Equation: y = (-2/3)x-7
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Equation of the perpendicular line thru (-6,-3):
-3 = (3/2)(-6) + b
-3 = -9 + b
b = 6
Equation: y = (3/2)x+6
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Cheers,
Stan H.
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