SOLUTION: This is a three part question. I wasn't too sure where to post it, so I posted the question here. Given the equation of the circle, label the center and radius of the circle. A

Algebra ->  Circles -> SOLUTION: This is a three part question. I wasn't too sure where to post it, so I posted the question here. Given the equation of the circle, label the center and radius of the circle. A      Log On


   



Question 266969: This is a three part question. I wasn't too sure where to post it, so I posted the question here.
Given the equation of the circle, label the center and radius of the circle.
A) X^2 + 2x + y^2 + 10y - 23 = 0

B) X^2 + 4X + y^2 - 12y = 24

C) X^2 + 10X + y^2 - 11 = 0

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

You must get these in the standard form
for a circle

%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2

Then the center is (h,k) and the radius is r.

A)  

x%5E2+%2B+2x+%2B+y%5E2+%2B+10y+-+23+=+0

Get the constant term on the right by
adding 23 to both sides:

x%5E2+%2B+2x+%2B+y%5E2+%2B+10y+=+23+

Multiply the coefficient of %22%22%2B2x,
which is 2 by 1%2F2, getting
2%2A%281%2F2%29=1. Then square 1,
getting 1%5E2=1 and add%22%22%2B1 to
both sides, putting it right after the
%22%22%2B2x on the left:

x%5E2+%2B+2x+%2B+1+%2B+y%5E2+%2B+10y+=+23%2B1+

Factor the first three terms on the left,
and combine the numbers on the right

%28x%2B1%29%28x%2B1%29+%2B+y%5E2+%2B+10y+=+24+

And write %28x%2B1%29%28x%2B1%29 as %28x%2B1%29%5E2

%28x%2B1%29%5E2+%2B+y%5E2+%2B+10y+=+24+

Multiply the coefficient of %22%22%2B10y,
which is 10 by 1%2F2, getting
10%2A%281%2F2%29=5.  Then square 5,
getting 5%5E2=25 and add%22%22%2B25 to
both sides, putting it right after the
%22%22%2B10y on the left:

%28x%2B1%29%5E2+%2B+y%5E2+%2B+10y+%2B25=+24%2B25+

Factor the last three terms on the left,
and combine the numbers on the right

%28x%2B1%29%5E2+%2B+%28y%2B5%29%28y%2B5%29+=+49+

And write %28y%2B5%29%28y%2B5%29 as %28y%2B5%29%5E2

%28x%2B1%29%5E2+%2B+%28y%2B5%29%5E2+=+49+

and write 49 as 7%5E2

%28x%2B1%29%5E2+%2B+%28y%2B5%29%5E2+=+7%5E2+, which we compare to

%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2+, and so

since -h=%22%22%2B1 then h=-1, and

since -k=%22%22%2B5 then k=-5, and r=7

so the center is (h,k) = (-1,-5) and the radius is r=7.




B)  x%5E2+%2B+4x+%2B+y%5E2+-+12y+=+24

Exactly the same way:

The constant term is already on the right,
so we don't have to get it over there.

Multiply the coefficient of %22%22%2B4x,
which is 4 by 1%2F2, getting
4%2A%281%2F2%29=2. Then square 2,
getting 2%5E2=4 and add%22%22%2B4 to
both sides, putting it right after the
%22%22%2B4x on the left:

x%5E2+%2B+4x+%2B+4+%2B+y%5E2+-+12y+=+24%2B4+

Factor the first three terms on the left,
and combine the numbers on the right

%28x%2B2%29%28x%2B2%29+%2B+y%5E2+-+12y+=+28+

And write %28x%2B2%29%28x%2B2%29 as %28x%2B2%29%5E2

%28x%2B2%29%5E2+%2B+y%5E2+-+12y+=+28+

Multiply the coefficient of -12y,
which is -12 by 1%2F2, getting
-12%2A%281%2F2%29=-6.  Then square -6,
getting %28-6%29%5E2=%22%22%2B36 and add%22%22%2B36 to
both sides, putting it right after the
-12y on the left:

%28x%2B2%29%5E2+%2B+y%5E2+-+12y+%2B36=+28%2B36+

Factor the last three terms on the left,
and combine the numbers on the right

%28x%2B2%29%5E2+%2B+%28y-6%29%28y-6%29+=+64+

And write %28y-6%29%28y-6%29 as %28y-6%29%5E2

%28x%2B2%29%5E2+%2B+%28y-6%29%5E2+=+64+

and write 64 as 8%5E2

%28x%2B2%29%5E2+%2B+%28y-6%29%5E2+=+8%5E2+, which we compare to

%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2+, and so

since -h=%22%22%2B2 then h=-2, and

since -k=%22%22-6 then k=6, and r=8

so the center is (h,k) = (-2,6) and the radius is r=8.


C) x%5E2+%2B+10x+%2B+y%5E2+-+11+=+0

This is just like the other except it'e a little
easier because we don't have to complete the square 
of y because there is no term in y, so we do something 
else there. But we begin the same way:

x%5E2+%2B+10x+%2B+y%5E2+-+11+=+0

Get the constant term on the right by
adding 11 to both sides:

x%5E2+%2B+10x+%2B+y%5E2+=+11+

Multiply the coefficient of %22%22%2B10x,
which is 10 by 1%2F2, getting
10%2A%281%2F2%29=5. Then square 5,
getting 5%5E2=25 and add%22%22%2B25 to
both sides, putting it right after the
%22%22%2B10x on the left:

x%5E2+%2B+10x+%2B+25+%2B+y%5E2++=+11%2B25+

Factor the first three terms on the left,
and combine the numbers on the right

%28x%2B5%29%28x%2B5%29+%2B+y%5E2+=+36+

And write %28x%2B5%29%28x%2B5%29 as %28x%2B5%29%5E2

%28x%2B5%29%5E2+%2B+y%5E2+=+36+

Now the only thing we have to do is write the
term y%5E2 as %28y-0%29%5E2

%28x%2B5%29%5E2+%2B+%28y-0%29%5E2+=+36+ 

Then write the 36 on the right as 6%5E2

%28x%2B5%29%5E2+%2B+%28y-0%29%5E2+=+6%5E2+, which we compare to

%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2+, and so

since -h=%22%22%2B5 then h=-5, and

since -k=%22%220 then k=0, and r=6

so the center is (h,k) = (5,0) and the radius is r=6.

Now be sure to learn how to do this by practicing on

some other problems like these, because even though I

can do your homework for you, I can't pass your tests

that you take in class for you, and your homework won't 

do you any good if you flunk the tests, because your 

teacher will then know you just got somebody to do your 

homework for you.

Edwin