SOLUTION: the line y=2x-2 meets the circle (x-2)^2 + (y-2)^2 =20 at A and B. coordinates of A and B are, (0,-2) and (4,6). show that AB is a diameter of the circle. thank you would be so h
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-> SOLUTION: the line y=2x-2 meets the circle (x-2)^2 + (y-2)^2 =20 at A and B. coordinates of A and B are, (0,-2) and (4,6). show that AB is a diameter of the circle. thank you would be so h
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Question 264546: the line y=2x-2 meets the circle (x-2)^2 + (y-2)^2 =20 at A and B. coordinates of A and B are, (0,-2) and (4,6). show that AB is a diameter of the circle. thank you would be so helpful if you could help, showing how you got the answer! thankyou Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! If you accept that they intersect at A and B, then all you need to show is that the distance from A to B is the diameter. so
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The square of the distance from A to B is
=
= 80
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It's the same length as the diameter, so it's thru the center of the circle.
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It was stated that A and B are on the circle and the line, so no proof of that was done.
