SOLUTION: the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line. please may you explain how you get to the answer aswel

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Question 264535: the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line. please may you explain how you get to the answer aswell, thankyou!
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the line y=2x-8 meets the coordinate axes at A and B. the line AB is a diameter of the circle. find the equation of the line.
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The line crosses the x-axis at y= 0, --> (4,0).
The line crosses the y-axis at x-0, --> (0,-8)
Those are the 2 points.
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The midpoint is the center of the circle.
To find the midpoint, get the average of x and y separately.
x: (0+4)/2 = 2
y: (0-8)/2 = -4
--> M (2,-4)
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The distance from M to A or B is the radius.
r%5E2+=+diffy%5E2+%2B+diffx%5E2
r%5E2+=+2%5E2+%2B+4%5E2+=+20
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--> %28x-2%29%5E2+%2B+%28y%2B4%29%5E2+=+20