SOLUTION: What is the equation for the cirlce with endpoints of a diameter are (-4,3) and (6,-8)?

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Question 261538: What is the equation for the cirlce with endpoints of a diameter are (-4,3) and (6,-8)?
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The equation of a circle is:
%28x+-+h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where (h, k) is the center of the circle and r is the radius. So we need the center and the radius of the circle to write the equation.

The center of a circle is always the midpoint of a diameter. So let's use the midpoint formula to find the center of the circle.
x%5Bm%5D+=+%28x%5B1%5D+%2B+x%5B2%5D%29%2F2 and y%5Bm%5D+=+%28y%5B1%5D+%2B+y%5B2%5D%29%2F2
x%5Bm%5D+=+%28-4+%2B+6%29%2F2 and y%5Bm%5D+=+%283+%2B+%28-8%29%29%2F2
x%5Bm%5D+=+2%2F2 and y%5Bm%5D+=+%28-5%29%2F2
x%5Bm%5D+=+1 and y%5Bm%5D+=+%28-5%29%2F2
So the center of the circle is (1, -5/2)

The radius of a circle is one-half the length of the diameter. We have the coordinates of the diameter so we can use the distance formula to find its length. And half of this length will be the radius we need. The distance formula is:
d+=+sqrt%28%28x%5B2%5D+-+x%5B1%5D%29%5E2+%2B+%28y%5B2%5D+-+y%5B1%5D%29%5E2%29
Substituting the coordinates into this we get:
d+=+sqrt%28%286+-+%28-4%29%29%5E2+%2B+%28-8+-+3%29%5E2%29
which simplifies as follows:
d+=+sqrt%28%2810%29%5E2+%2B+%28-11%29%5E2%29
d+=+sqrt%28100+%2B+121%29
d+=+sqrt%28221%29
This is the length of the diameter. The radius will be 1/2 of this:
r+=+sqrt%28221%29%2F2

Now that we have the center of the circle and the length of the radius, we can substitute these values into %28x+-+h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2:
%28x+-+1%29%5E2+%2B+%28y+-+%28-5%2F2%29%29%5E2+=+%28sqrt%28221%29%2F2%29%5E2
which simplifies to:
%28x+-+1%29%5E2+%2B+%28y+%2B+5%2F2%29%5E2+=+221%2F4